i ve got this dyno graph from a dyno dynamics dyno and the torque reading is in tractive effort (N) im trying to convert to foot pounds but the reading on the graph is a max of 5500 (N) which seems a odd measurement not the normal newton metres which would be a way lower number
thanks adam deb
66deluxe ·
I found this for you,
The formula is:
T = (TE x r)/(1000 x R)
The tractive effort is obtained by multiplying the torque by the total ratio of power train and dividing this sum by the rolling radius of the driving tyres.
T = (TE x r)/(1000 x R)
Where:
T= Motor torque in kg/millimetres
TE = Tractive Effort in N
R = Overall gear reduction including both axle and transmission
r = Rolling radius of loaded driving tyre in millimetres
Example:
TE = 5400
R = diff ratio X gear ratio (eg 3.45 diff x 1.00 Auto 3rd gear = 3.45)
r = 326.60 mm (18" rim/ with 235/40/18 tyre combo)
T = 510NM
So you need to know:
diff ratio
what gear the run was in, and it's ratio
what rear tyre size is (and convert that to radius in mm)